Optimal. Leaf size=116 \[ -\frac{\cos (c+d x)}{a^2 d}+\frac{2 \cot ^3(c+d x)}{3 a^2 d}-\frac{2 \cot (c+d x)}{a^2 d}+\frac{9 \tanh ^{-1}(\cos (c+d x))}{8 a^2 d}-\frac{\cot (c+d x) \csc ^3(c+d x)}{4 a^2 d}+\frac{\cot (c+d x) \csc (c+d x)}{8 a^2 d}-\frac{2 x}{a^2} \]
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Rubi [A] time = 0.281237, antiderivative size = 116, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 7, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.241, Rules used = {2875, 2872, 3770, 3767, 8, 3768, 2638} \[ -\frac{\cos (c+d x)}{a^2 d}+\frac{2 \cot ^3(c+d x)}{3 a^2 d}-\frac{2 \cot (c+d x)}{a^2 d}+\frac{9 \tanh ^{-1}(\cos (c+d x))}{8 a^2 d}-\frac{\cot (c+d x) \csc ^3(c+d x)}{4 a^2 d}+\frac{\cot (c+d x) \csc (c+d x)}{8 a^2 d}-\frac{2 x}{a^2} \]
Antiderivative was successfully verified.
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Rule 2875
Rule 2872
Rule 3770
Rule 3767
Rule 8
Rule 3768
Rule 2638
Rubi steps
\begin{align*} \int \frac{\cos ^3(c+d x) \cot ^5(c+d x)}{(a+a \sin (c+d x))^2} \, dx &=\frac{\int \cot ^4(c+d x) \csc (c+d x) (a-a \sin (c+d x))^2 \, dx}{a^4}\\ &=\frac{\int \left (-2 a^6-a^6 \csc (c+d x)+4 a^6 \csc ^2(c+d x)-a^6 \csc ^3(c+d x)-2 a^6 \csc ^4(c+d x)+a^6 \csc ^5(c+d x)+a^6 \sin (c+d x)\right ) \, dx}{a^8}\\ &=-\frac{2 x}{a^2}-\frac{\int \csc (c+d x) \, dx}{a^2}-\frac{\int \csc ^3(c+d x) \, dx}{a^2}+\frac{\int \csc ^5(c+d x) \, dx}{a^2}+\frac{\int \sin (c+d x) \, dx}{a^2}-\frac{2 \int \csc ^4(c+d x) \, dx}{a^2}+\frac{4 \int \csc ^2(c+d x) \, dx}{a^2}\\ &=-\frac{2 x}{a^2}+\frac{\tanh ^{-1}(\cos (c+d x))}{a^2 d}-\frac{\cos (c+d x)}{a^2 d}+\frac{\cot (c+d x) \csc (c+d x)}{2 a^2 d}-\frac{\cot (c+d x) \csc ^3(c+d x)}{4 a^2 d}-\frac{\int \csc (c+d x) \, dx}{2 a^2}+\frac{3 \int \csc ^3(c+d x) \, dx}{4 a^2}+\frac{2 \operatorname{Subst}\left (\int \left (1+x^2\right ) \, dx,x,\cot (c+d x)\right )}{a^2 d}-\frac{4 \operatorname{Subst}(\int 1 \, dx,x,\cot (c+d x))}{a^2 d}\\ &=-\frac{2 x}{a^2}+\frac{3 \tanh ^{-1}(\cos (c+d x))}{2 a^2 d}-\frac{\cos (c+d x)}{a^2 d}-\frac{2 \cot (c+d x)}{a^2 d}+\frac{2 \cot ^3(c+d x)}{3 a^2 d}+\frac{\cot (c+d x) \csc (c+d x)}{8 a^2 d}-\frac{\cot (c+d x) \csc ^3(c+d x)}{4 a^2 d}+\frac{3 \int \csc (c+d x) \, dx}{8 a^2}\\ &=-\frac{2 x}{a^2}+\frac{9 \tanh ^{-1}(\cos (c+d x))}{8 a^2 d}-\frac{\cos (c+d x)}{a^2 d}-\frac{2 \cot (c+d x)}{a^2 d}+\frac{2 \cot ^3(c+d x)}{3 a^2 d}+\frac{\cot (c+d x) \csc (c+d x)}{8 a^2 d}-\frac{\cot (c+d x) \csc ^3(c+d x)}{4 a^2 d}\\ \end{align*}
Mathematica [A] time = 1.83727, size = 219, normalized size = 1.89 \[ -\frac{\sin ^5(c+d x) \left (\csc \left (\frac{1}{2} (c+d x)\right )+\sec \left (\frac{1}{2} (c+d x)\right )\right )^4 \left (192 \cot (c+d x)+(3 \csc (c+d x)-8) \csc ^4\left (\frac{1}{2} (c+d x)\right )+(128-6 \csc (c+d x)) \csc ^2\left (\frac{1}{2} (c+d x)\right )+8 \left (-(8 \cos (c+d x)+7) \sec ^4\left (\frac{1}{2} (c+d x)\right )-6 \sin ^4\left (\frac{1}{2} (c+d x)\right ) \csc ^5(c+d x)+3 \sin ^2\left (\frac{1}{2} (c+d x)\right ) \csc ^3(c+d x)+3 \csc (c+d x) \left (16 (c+d x)+9 \log \left (\sin \left (\frac{1}{2} (c+d x)\right )\right )-9 \log \left (\cos \left (\frac{1}{2} (c+d x)\right )\right )\right )\right )\right )}{3072 a^2 d (\sin (c+d x)+1)^2} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.167, size = 173, normalized size = 1.5 \begin{align*}{\frac{1}{64\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{4}}-{\frac{1}{12\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{3}}+{\frac{5}{4\,d{a}^{2}}\tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) }-2\,{\frac{1}{d{a}^{2} \left ( 1+ \left ( \tan \left ( 1/2\,dx+c/2 \right ) \right ) ^{2} \right ) }}-4\,{\frac{\arctan \left ( \tan \left ( 1/2\,dx+c/2 \right ) \right ) }{d{a}^{2}}}-{\frac{1}{64\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{-4}}+{\frac{1}{12\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{-3}}-{\frac{5}{4\,d{a}^{2}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{-1}}-{\frac{9}{8\,d{a}^{2}}\ln \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.54064, size = 355, normalized size = 3.06 \begin{align*} \frac{\frac{\frac{16 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - \frac{3 \, \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} - \frac{224 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} - \frac{384 \, \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} - \frac{240 \, \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}} - 3}{\frac{a^{2} \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} + \frac{a^{2} \sin \left (d x + c\right )^{6}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{6}}} + \frac{\frac{240 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - \frac{16 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac{3 \, \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}}}{a^{2}} - \frac{768 \, \arctan \left (\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1}\right )}{a^{2}} - \frac{216 \, \log \left (\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1}\right )}{a^{2}}}{192 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.14847, size = 513, normalized size = 4.42 \begin{align*} -\frac{96 \, d x \cos \left (d x + c\right )^{4} + 48 \, \cos \left (d x + c\right )^{5} - 192 \, d x \cos \left (d x + c\right )^{2} - 90 \, \cos \left (d x + c\right )^{3} + 96 \, d x - 27 \,{\left (\cos \left (d x + c\right )^{4} - 2 \, \cos \left (d x + c\right )^{2} + 1\right )} \log \left (\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right ) + 27 \,{\left (\cos \left (d x + c\right )^{4} - 2 \, \cos \left (d x + c\right )^{2} + 1\right )} \log \left (-\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right ) - 32 \,{\left (4 \, \cos \left (d x + c\right )^{3} - 3 \, \cos \left (d x + c\right )\right )} \sin \left (d x + c\right ) + 54 \, \cos \left (d x + c\right )}{48 \,{\left (a^{2} d \cos \left (d x + c\right )^{4} - 2 \, a^{2} d \cos \left (d x + c\right )^{2} + a^{2} d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.29527, size = 215, normalized size = 1.85 \begin{align*} -\frac{\frac{384 \,{\left (d x + c\right )}}{a^{2}} + \frac{216 \, \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) \right |}\right )}{a^{2}} + \frac{384}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1\right )} a^{2}} - \frac{450 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} - 240 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 16 \, \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 3}{a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4}} - \frac{3 \, a^{6} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} - 16 \, a^{6} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 240 \, a^{6} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )}{a^{8}}}{192 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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